Friday Nov 17
The number of p-Sylows is congruent to 1 mod p, and divides |G| / pk.
Every p-subgroup is in a Sylow.
Sylow subgroups are all conjugate.
They're normal iff they're unique.
If |G|=2p, p an odd prime, then G is either Z2p or Dp.
Every p-subgroup is in a Sylow.
Sylow subgroups are all conjugate.
They're normal iff they're unique.
If |G|=2p, p an odd prime, then G is either Z2p or Dp.
0 Comments:
Post a Comment
<< Home